Hi guys . I m Tajinderpreet i m going to write about rational root theorem .
RATIONAL ROOT THEOREM
The
rational root theorem, or Rational Root Test can be used to do
a quick check whether a polynomial has
rational roots.
A
root or zero of a function is a number that, when plugged in for the
variable, makes the function equal to zero. Thus, the roots of a
polynomial P(x) are values of x such that P(x) = 0 .
Steps
:-
- Arrange the polynomial in descending order.
- Write down all the factors of the constant term. These are all the possible values of p .
- Write down all the factors of the leading coefficient. These are all the possible values of q .
- Write down all the possible values of . Remember that since factors can be negative, and - must both be included. Simplify each value and cross out any duplicates.
- Use synthetic division to determine the values of for which P() = 0 . These are all the rational roots of P(x) .
Here is some examples :-
.
Example:
Find all the rational zeros of P(x) = x 3
-9x + 9 + 2x 4
-19x 2
.
P1. P(x)
= 2x 4
+ x 3
-19x 2
- 9x + 9
Factors
of constant term: ±1 , ±3 , ±9 .
Factors
of leading coefficient: ±1 , ±2 .
possible
values of p ; +1 + 1 +3 + 3 +9 +9 .
q
1 2 1 2 1 2
Use
synthetic division:
divide by 1 ) 2 1 -19 -9 9
2 3 -16 -25
2
3 -16 -25 -16
Remainder
= -16 . not zero
divide by -1) 2 1 -19 -9 9
-2 1 18 -9
2
-1 -18 9 0
Remainder
=0 . is zero
divide by 1/2) 2 1 -19 -9 9
1 1 -9 -9
2
2 -18 9 0
Remainder
= 0 . is zero
divide by -1/2) 2 1 -19 -9 9
1 0 19/2 -1/4
2
0 -19 1/2 35/4
Remainder
= 35/4 . not zero
divide by 3) 2 1 -19 -9 9
6 21 6 -9
2 7 2 -3 0
Remainder
=0 .is zero
Thus,
the rational roots of P(x) are x = - 3 , -1 , , and 3 .
We
can often use the rational zeros theorem to factor a polynomial.
Using synthetic division, we can find one real root a and we can find
the quotient when P(x) is divided by x - a . Next, we can use
synthetic division to find one factor of the quotient. We can
continue this process until the polynomial has been completely
factored.
Example
: 2
Consider:
x2-3x+2=0
If
this has rational roots p/q (which we know it has), then p is a
factor of 2 and q is a factor of 1.
So
the roots are some combination of the factors in the fraction below:
We
must use all the numbers, that is we need to use both 1 and 2 to make
possible roots. Where all the roots are rational, we cannot use just
the "1" as a numerator. We need to use the 2 also. So 1 and
1 won't do as numerators, although 2 and 2 are possible (because the
1 is always automatically included in any integer.)
We
test each of the roots in the original equation and, in this case, we
find x=1/1 or 2/1, which are 1 and 2, of course.
HOPE this will help you :)
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